#### 610 insects

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• Multiply by the initial population:
• \( 200 \times 3.052 \approx 610.4 \)
• insects
• A virologist is testing a new antiviral drug that reduces the viral load by 40% every day. If the initial viral load is 10,000 particles, what will be the viral load after 5 days?
• Determine the daily remaining percentage:
• Remaining = \( 100\% - 40\% = 60\% = 0.60 \)

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$ Y_5 = 871 + 72.9 = 943.9 $$ Y_6 = 943.9 + 65.61 = 1009.51 $ — but we want only 5 seasons.+ 690 = 1290+ 843.9 = 1614.9+ 909.51 = 4014.41#### 4014.41$ (n-1) \log(1.125) > \log(1.484375) $$ \log(1.125) \approx 0.051161 $$ \log(1.484375) \approx 0.17116 $$ (1.125)^k > 1.484375 $