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2c + d &= 50 \quad \text{(Equation 1)} \\5c + d &= 110 \quad \text{(Equation 2)}3c = 60c = \frac{60}{3} = 20Substitute \( c = 20 \) back into Equation 1:2(20) + d = 50+ d = 50d = 50 - 40 = 10Thus, the values of \( c \) and \( d \) are:\boxed{c = 20, \ d = 10}