\frac{7}{5} = \frac{21}{x}
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- The ratio of capsid protein A to capsid protein B is \(7:5\). This means for every 7 molecules of protein A, there are 5 molecules of protein B.
- Given 21 molecules of protein A, we find the corresponding number of protein B molecules.
- Let the number of protein B molecules be \(x\). Then:
- 7x = 21 \times 5 = 105
- x = \frac{105}{7} = 15
- There are 15 molecules of protein B. The total number of molecules is:
