\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]
![\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]](https://soloferat.biz.id/images/rx--fracddxlnx2--4x--5--frac2x--4x2--4x--5-.jpg)
Related Articles
- A health data analyst models patient recovery rates with the function \( R(x) = \ln(x^2 + 4x + 5) \). Find the value of \( x \) that maximizes \( R(x) \).
- To maximize \( R(x) = \ln(x^2 + 4x + 5) \), we first find the derivative \( R'(x) \) and set it to zero.
- Differentiate \( R(x) \):
- Set the derivative to zero:
- \[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]
- The numerator must be zero, so:
Trending Articles
GTA V vs S95: Find Out Which Game Wins
Is S95 the New King? Gearing Up Against GTA V
Crack the Code: William Hjortsberg's Game Hidden Lore
The Fallen Angel of William Hjortsberg: His Dark Game Legacy
island of succubi: did you fall for the trap?
Hornet No Cloak Hidden: Developer Secret Weapon You Haven’t Seen
warning: succubus trap island contains demonic temptations
William Hjortsberg's Game: Secrets Behind the Falling Angel
The Battle of Nancy: What Really Changed History
succubus trap island: escape the island or succumb to pleasure?